Question : The coordinates of a moving particle at any time t are given by x=αt3 and y=βt3. The speed of the particle at time t is given by ________.
Doubt by Yashika
Solution :
x=αt3
vx = d(αt3)/dt
vx = 3αt2
y=βt3
vy=d(βt3)/dt
vy=3βt2
Now
v = vx i + vy j
v = 3αt2 i + 3βt2 j
Speed of the particle means magnitude of v
v = √[vx2 + vy2]
v = √[(3αt2)2 + (3βt2)]
v = √[9α2t4 + 9β2t4]
v = √9t4(α2 + β2)
v = 3t2√(α2 + β2)
Doubt by Yashika
Solution :
x=αt3
vx = d(αt3)/dt
vx = 3αt2
y=βt3
vy=d(βt3)/dt
vy=3βt2
Now
v = vx i + vy j
v = 3αt2 i + 3βt2 j
Speed of the particle means magnitude of v
v = √[vx2 + vy2]
v = √[(3αt2)2 + (3βt2)]
v = √[9α2t4 + 9β2t4]
v = √9t4(α2 + β2)
v = 3t2√(α2 + β2)