Question : Two substances of masses m and 2m, specific heat 2c and c respectively are at temperature T1 and T2. If these are brought in contact then find the temperature of mixture at thermal equilibrium if T1>T2.
Doubt by Muskan
Solution :
Let T be the temperature of mixture at thermal equilibrium.
Let T be the temperature of mixture at thermal equilibrium.
According to the principle of Calorimetry
Heat lost by the Hot body = Heat gained by the cold body
m1c1ΔT1=m2c2ΔT2
m(2c)(T1-T)=2m(c)(T-T2)
T1-T=T-T2
T1+T2=T+T
m(2c)(T1-T)=2m(c)(T-T2)
T1-T=T-T2
T1+T2=T+T
T1+T2=2T
T = (T1+T2)/2
T = (T1+T2)/2