A wave is represented as y=5sin(10t+π/4) . . .

Question : A wave is represented as y=5sin(10t+π/4). Find the
a) velocity of the particle
b) acceleration of the particle.

Doubt by Ananya

Solution : 
Equation of wave is 
y=5sin(10t+π/4)

a) Velocity of the wave 
v=dy/dt
v=d[
5sin(10t+π/4)]/dt
v=5cos(10t+π/4)×10
v=50cos(10t+π/4)

b) Acceleration of the wave
a=dv/dt
a=d[
50cos(10t+π/4)]/dt
a=50[(-sin(10t+π/4)]×10
a=-500sin(10t+π/4)