If system shown in the figure is in equilibrium then find . . .

Question : If system shown in the figure is in equilibrium then find ⅓[m2/m1]?

Doubt by Suhani

Solution : 

It is given  that the system is in equilibrium. 

It means both the mass m₁ and m₂ are in equilibrium i.e. net force on both the masses is zero. 

For Mass m₁

T=m₁g — (1)

For Mass m₂

T+2T+4T+8T=m₂g
15T=m₂g — (2)

Dividing equation (2) by (1)
15T/T = m₂g/m₁g
15=m₂/m₁
Dividing both sides by 3
15/3=⅓[m₂/m₁]
5=⅓[m₂/m₁]

Hence, the value of ⅓[m2/m1] is 5