Doubt by Rohan
Solution :
A.B=6
ABcosθ=6 — (1)
|A×B|=8
ABsinθ=8—(2)
Dividing equation (2) by (1)
ABsinθ/ABcosθ = 8/6
sinθ/cosθ = 4/3
tanθ=4/3
Using the concept of Trigonometry
sinθ=4/5
Putting in equation (2)
AB(4/5)=8
AB=(8×5)/4
AB=40/4
AB=10
Hence, (b) 10, would be the correct option.