Question : The position of a body moving along x-axis at time t is given by x=(t²-4t+6) m. The distance travelled by body in time interval t=0 to t=3 sec is
(1) 5 m
(2) 7 m
(3) 4 m
(4) 3 m
Doubt by Tanishq
Solution :
x=(t²-4t+6) m
Distance travelled by the body at t=0 sec
x1=(0)²-4(0)+6
x1=6m
x1=(0)²-4(0)+6
x1=6m
Distance travelled by the body at t=3 sec
x2=(3)²-4(3)+6
x2=9-12+6
x2=15-12
x2=3 m
x=(t²-4t+6) m
x2=9-12+6
x2=15-12
x2=3 m
x=(t²-4t+6) m
v=dx/dt
v=d(t²-4t+6)/dt
v=2t-4
0=2t-4
-2t=-4
t=-4/-2
t=2 sec
v=d(t²-4t+6)/dt
v=2t-4
0=2t-4
-2t=-4
t=-4/-2
t=2 sec
Distance covered by the body at t=2sec
x3=(2)²-4(2)+6
x3=4-8+6
x3=10-8
x3=2 m
x3=(2)²-4(2)+6
x3=4-8+6
x3=10-8
x3=2 m
Distance covered
From t=0 to t=2sec
6 m to 2m
=|2-6| = 4 m
From t=0 to t=2sec
6 m to 2m
=|2-6| = 4 m
Distance covered
From t=2sec to t=3sec
2 m to 3 m
=|3-2| = 1 m
From t=2sec to t=3sec
2 m to 3 m
=|3-2| = 1 m
Total Distance Covered
= 4+1
= 4+1
= 5 m
So, (1) 5 m, would be the correct opiton.
Similar Question :
The displacement of a particle is given by
x=(t-2)² where x is in metres and t in seconds. The distance covered by the particle in first 4 seconds is
(a) 4 m
x=(t-2)² where x is in metres and t in seconds. The distance covered by the particle in first 4 seconds is
(a) 4 m
(b) 8 m
(c) 12 m
(d) 16 m
(c) 12 m
(d) 16 m