An object falling through a fluid observed to have acceleration given by a=g-bv . . .

Question : An object falling through a fluid observed to have acceleration given by a=g-bv where g is the gravitational acceleration and b is a constant. After a long time it is observed to fall with constant velocity. what would be the value of this constant velocity?

Doubt by Divya 

Solution : 

We know, 
a=g-bv


Hence, the value of constant velocity would be g/b. 

Alternate Method : 
a=g-bv — (1) 
After long time velocity becomes constant so 
a=dv/dt
a=d(const)/dt
a=0
Putting in equation (1) 
0=g-bv
bv=g
v=g/b
Hence, the value of constant velocity would be g/b.