Doubt by Yana
Solution :
Let initial velocity of the object be 'u' and uniform acceleration be 'a'
We know,
We know,
v=u+at
Case I :
t=5 sec
v=25 m/s
t=5 sec
v=25 m/s
v=u+at
25=u+a(5)
25=u+a(5)
25=u+5a — (1)
Case II :
t=8 sec
v=34 m/s
Case II :
t=8 sec
v=34 m/s
v=u+at
34=u+a(8)
34=u+a(8)
34=u+8a — (2)
Solving equation (1) and (2)
34=u+8a
25=u+5a
- - -
-----------------
9 = 0 + 3a
-----------------
3a=9
a=9/3
a=3 m/s²
- - -
-----------------
9 = 0 + 3a
-----------------
3a=9
a=9/3
a=3 m/s²
putting in equation (1)
25=u+5(3)
25=u+15
25-15=u
10=u
u=10 m/s
25=u+15
25-15=u
10=u
u=10 m/s
We know, distance covered by a body in nth second is given by


The distance travelled by the object in 10th second is 38.5 m