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A bullet fired at an angle of 30° with the horizontal hits the . . .

Question : A bullet fired at an angle of 30° with the horizontal hits the ground 3/√3 km away. Can we hit a target at a distance of 6 km by adjusting its angle of projection?


Doubt by Yana

Solution : 

θ=30°
R=3/√3 km = √3 km 

We know, 


u²=2g — (1) 

Also, 
Maximum Range of projectile is given by 



Since the maximum range of the projectile is just 2 km, so we can't hit the target which is 6 km away by just adjusting its angle of projection.