Question : Springs A and B are identical except that A is stiffer than B, i.e. force constant KA>KB. In which spring more work is expected if they are streched by the same amount? Explain. [Mothers Global 2024]
Doubt by Raghav
Solution :
KA>KB (Given)
We know,
Potential Energy or Work done in stretching a spring by displacement x is given by ½kx²
Potential Energy or Work done in stretching a spring by displacement x is given by ½kx²
W=½kx²
Here both the springs are stretched by equal amount so
W∝k
∵KA>KB
∴WA>WB
Here both the springs are stretched by equal amount so
W∝k
∵KA>KB
∴WA>WB
Hence, more work is expected in the case of spring A.