Question : What amount of heat must be supplied to 2.0×10-2 Kg of nitrogen (at room temperature) to raise its temperature by 45°C at constant pressure? (Molecular Mass of N2 is 28, R=8.3 Jmol-1K-1.)
Doubt by Vaibhav
Solution :
m = 0.02 kg = 20 g
We know
ΔQ = nCPΔT
ΔQ = (m/M)CPΔT
ΔQ = (m/M)(7R/2)ΔT
[∵ For Monoatomic Gas, CP = 7R/2]
ΔQ = [7mRΔT]/[2M]
ΔQ = [7×20×8.3×45]/[2×28]
ΔQ = [7×83×45]/[28]
ΔQ = [26145]/[28]
ΔQ = 933.75 J
ΔQ = nCPΔT
ΔQ = (m/M)CPΔT
ΔQ = (m/M)(7R/2)ΔT
[∵ For Monoatomic Gas, CP = 7R/2]
ΔQ = [7mRΔT]/[2M]
ΔQ = [7×20×8.3×45]/[2×28]
ΔQ = [7×83×45]/[28]
ΔQ = [26145]/[28]
ΔQ = 933.75 J